x+2x分之x^2+2x+1除x-1分之x^2-1-x+2分之1,其中x=根号2的平方-2

问题描述:

x+2x分之x^2+2x+1除x-1分之x^2-1-x+2分之1,其中x=根号2的平方-2
1个回答 分类:数学 2014-12-10

问题解答:

我来补答
x+2分之x^2+2x+1除x-1分之x^2-1-x+2分之1
=(x^2+2x+1)/(x+2)÷(x^2-1)/(x-1)-1/(x+2)
=(x+1)^2/(x+2)乘(x-1)/(x+1)(x-1)-1/(x+2)
=(x+1)/(x+2)-1/(x+2)
=x/(x+2)
x=根号2的平方-2
=√(2²-2)=√2
原式
=√2/(2+√2)
=1/(√2+1)
=√2-1
 
 
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