帮帮忙导数证明题已知m为正整数,用导数证明,当X>-1时,(1+X)^m>=1+mX

f(x)= (1+X)^m-(1+mX)
f’(x)= m (1+X)^(m-1) –m
=m[(1+X)^(m-1) –1]
-1=f min=0
当X>-1时,(1+X)^m>=1+mX