如果a=3又6之5,b=须5又7分之1,c=负2又6分之1,d=32又7分之6,求a十(一b)十(一|c|)十[一(一d

a+ ( -b ) + ( - |c| ) + [ - (-d) ]
=a-b-c+d
=3又6分之5+5又7分之1+2又6分之1+32又7分之6
=6+38
=44