问题描述: 化简:1-sin6α(六次方)-cos6(六次方)α/1-sin4(四次方)α-cos4(四次方)α 1个回答 分类:数学 2014-10-11 问题解答: 我来补答 (1-cos^6α-sin^6α)/(1-cos^4α-sin^4α)1=sin^2α+cos^2α 原式=(sin^2α+cos^2α-cos^6α-sin^6α) /(sin^2α+cos^2α-cos^4α-sin^4α)分母=sin^2α(1-sin^2α)+cos^2α(1-cos^2α)=2sin^2αcos^2α 分子=sin^2α(1-sin^4α)+cos^2α(1-cos^4α) sin^2α(1-sin^4α)=sin^2α(1-sin^2α)(1+sin^2α)=sin^2αcos^2α(1+sin^2α) 同理cos^2α(1-cos^4α)=sin^2αcos^2α(1+cos^2α) 原式=sin^2αcos^2α(1+sin^2α+1+cos^2α)/2sin^2αcos^2α=3/2 展开全文阅读