问题描述: 若函数fx=2x+1分之1-x的值域是具体方法! 1个回答 分类:综合 2014-11-12 问题解答: 我来补答 f(x)=(-x-0.5+1.5)/[2(x+0.5)]=[-(x+0.5)+1.5]/[2(x+0.5)]=-(x+0.5)/[2(x+0.5)]+1.5/[2(x+0.5)]=-1/2+3/(4x+2)3/(4x+1)≠0所以-1/2+3/(4x+)≠-1/2所以值域(-∞,-1/2)∪(-1/2,+∞) 展开全文阅读