如图△ABC是等腰三角形AB=AC分别以两腰为边向外作等边三角形,ABD与等边三角形ACE已知∠DAE=∠DBC的三个内

因为ABD、ACE为等边三角形,所以∠DAB=∠CAE=∠DBA=60
又因为∠DAE=∠DBC,所以120+∠BAC＝60+∠ABC,
因为AB=AC,所以∠ABC＝∠ACB
又因为∠BAC=180-2∠ABC,所以120+180-2∠ABC＝60+∠ABC,化简得3∠ABC＝240,
∠ABC＝∠ACB＝80,∠BAC=180-2∠ABC＝20