3 log(3根号5的次方)+根号3 (log31/5的次方)

a^loga(N)=N
所以原式=√5+[3^(1/2)]^[log3(1/5)]
=√5+3^[(1/2)*log3(1/5)]
=√5+3^log3(1/5)^(1/2)]
=√5+(1/5)^(1/2)
=√5+1/√5
=(6/5)√5