#include main() { char *p[]={ "BOOL","OPK","H","SP"}; int i;

问题描述:

#include main() { char *p[]={ "BOOL","OPK","H","SP"}; int i; for(i=3; i>=0; i--,i--) p
#include
main()
{ char *p[]={ "BOOL","OPK","H","SP"};
int i;
for(i=3; i>=0; i--,i--) printf( "%c",*p[i]);
printf("\n");
}
1个回答 分类:综合 2014-10-11

问题解答:

我来补答
输出SO,
i为3,*p[3]为S
自减后i为1,*p[1] 为O
 
 
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