对数计算1.{log(4)（3）+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(

1.
[log4(3) + log8(3)]×[log3(2) + log9(2)]
= [(1/2)·log2(3) + (1/3)·log2(3)]·[log3(2) +(1/2)· log3(2)]
= (5/6)·log2(3)·(3/2)log3(2)
= [(5/6)·(3/2)]·[log2(3)·log3(2)]
= (5/4)·(1)
= 5/4
2.
log2(3)× [log3(4) + log9(2)]
= log2(3)·[2·log3(2) + (1/3)·log3(2)]
= log2(3)·[(7/3)·log3(2)]
= (7/3)[log2(3)·log3(2)]
= 7/3
3.请输入正确的格式