初一数学(乘法公式的综合运用)

问题描述:

初一数学(乘法公式的综合运用)
一.计算
(-2x+y)(-2x-y)(4x²-y²)
(a+2b)(a-2b)-(a-3b)²
(x-y)²-(y+2x)(y-2x)
(2a-1/3)(4a²-1/9)(2a+1/3)
(x+y)²9+(2x+y)(2x-y)-2(2x²-xy)
(x+y)²(x-y)²-(x+y)(x-y)(x²+y²)
(a+b-4)(a+b+4)
(-2m-n)(2m+n)
(2-3a²)(3a²-2)
以下不用步骤
二.填空.
已知x²+y²=4,x+y=3,则xy的值( )
若a²+b²=7,ab=3,则(a+b)²=( )
若m-n=2,则3m²-6mn+3n²-7的值( )
1个回答 分类:数学 2014-12-10

问题解答:

我来补答
一.计算
(-2x+y)(-2x-y)(4x²-y²)
=(4x²-y²)²
=16x^4-8x²y²+y^4
(a+2b)(a-2b)-(a-3b)²
=a²-4b²-a²+6ab-9b²
=6ab-13b²
(x-y)²-(y+2x)(y-2x)
=x²-2xy+y²-y²+4x²
=5x²-2xy
(2a-1/3)(4a²-1/9)(2a+1/3)
=(4a²-1/9)²
=16a^4-8a²/9+1/81
(x+y)²+(2x+y)(2x-y)-2(2x²-xy)
=x²+2xy+y²+4x²-y²-4x²+2xy
=x²+4xy
(x+y)²(x-y)²-(x+y)(x-y)(x²+y²)
=(x²-y²)²-(x²-y²)(x²+y²)
=x^4-2x²y²+y^4-x^4+y^4
=-2x²y²+2y^4
(a+b-4)(a+b+4)
=a²-(b-4)²
=a²-b²+8b-16
(-2m-n)(2m+n)
=-(2m+n)²
=-4m²-4mn-n²
(2-3a²)(3a²-2)
=-(3a²-2)²
=-9a^4+12a²-4
二.填空.
已知x²+y²=4,x+y=3,则xy的值(5/2)
若a²+b²=7,ab=3,则(a+b)²=(13)
若m-n=2,则3m²-6mn+3n²-7的值(5)
 
 
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