问题描述： 参数方程x=t+1/t-1 y=2t/t^3-1怎么化普通方程 1个回答 分类：数学 2014-09-24 问题解答： 我来补答 x-1=(t+1)/(t-1)-1=2/(t-1)t-1=2/(x-1)t=(x+1)/(x-1)t^2+t+1=(x+1)^2/(x-1)^2+(x+1)/(x-1)+1=(3x^2+1)/(x-1)^2所以t^3-1=(t-1)(t^2+t+1)=[2/(x-1)][(3x^2+1)/(x-1)^2]所以y=2[(x+1)/(x-1)]/[2/(x-1)][(3x^2+1)/(x-1)^2]=(x+1)(x-1)^2/(3x^2+1) 展开全文阅读
