求函数渐近线有两条斜渐近线,要求给出渐近线方程.

lim(x->+∞) f(x)/x= lim(x->+∞) [(x-1)/x]e^(π/2+arctanx)
=e^(π/2+π/2)
=e^π
且lim(x->+∞) [f(x)-(e^π)x]=lim(x->+∞) [(e^π)(x-1)-(e^π)x]= -e^π
所以一条是y=(e^π)x-e^π
lim(x->-∞) f(x)/x= lim(x->-∞) [(x-1)/x]e^(π/2+arctanx)
=e^(π/2-π/2)
=1
且lim(x->-∞) [f(x)-x]=lim(x->-∞) [(x-1)-x]= -1
所以另一条是y=x-1
满意请采纳,谢谢支持.