在三角形abc中.已知a=2,b=2根号2,C=15°,求角A、B和边c的值

cos15=cos(45-30)
=cos45cos30+sin45sin30
=(√6+√2)/4
c²=a²+b²-2abcosC
=4+8-8√2*(√6+√2)/4
=12-4√3-4
=8-2√12
=(√6-√2)²
c=√6-√2
sin15=sin(45-30)=sin45cos30-cos45sin30=(√6-√2)/4
a/sinA=c/sinC
2/sinA=(√6-√2)/[(√6-√2)/4]=4
sinA=1/2
因为a