问题描述: (log2 3+log4 9+log8 27+...+log2^n 3^n)log9 32的N次方根 1个回答 分类:数学 2014-12-08 问题解答: 我来补答 log4 9=2lg3/2lg2 =lg3/lg2=log2 3log2 3+log4 9+log8 27+...+log2^n 3^n=nlog2 3=nlg3/lg2log9 32的N次方根(log2 3+log4 9+log8 27+...+log2^n 3^n)log9 32的N次方根=(1/n)(5lg2/2lg3)*nlg3/lg2=5/2 展开全文阅读