设n为自然数,n!=1*2*3*...*(n-1)*n称为n的阶乘,并且0!=1.试编写程序计算2!,4!,10!,并将

function y = tapmulti(cnt)
y = 1;
if cnt ~= 0
for i0 = 1:cnt
y = y*i0;
end
end
end
另外一个程序用
cn1 = tapmulti(2)
cn2 = tapmulti(4)
cn3 = tapmulti(10)