问题描述: 求极限 3n^2-4n+4/2-n^2 1个回答 分类:数学 2014-11-27 问题解答: 我来补答 (3n^2-4n+4)/(2-n^2)=(3n^2-6-4n+10)/(2-n^2)=-3+(10-4n)/(2-n^2)=-3-(4/n+10/n^2)/(-1+2/n^2)n趋向于无穷大,-4/n+10/n^2趋向于0,2/n^2-1趋向于-1lim(3n^2-4n+4)/(2-n^2)=-3 展开全文阅读