已知log以2为底的3是a,log以3为底的7是b,试用a,b表示log以14为底的56

log以14为底的56
＝log以3为底的56/log以3为底的14
=(log以3为底的7+3log以3为底的2)/(log以3为底的2+log以3为底的7)
=(b+3/a)/(1/a+b)
=(ab+3)/(ab+1)
log以2为底的3=lg3/lg2=a
log以3为底的2=lg2/lg3=1/a
不懂的欢迎追问,