当2a+b/3a-b=2时,求代数式2a+b/2(3a-b)+3a-b/3(2a+b)

(2a+b)/(3a-b)=2
2a+b=6a-2b
4a=3b
a=3b/4
代入(2a+b)/[2(3a-b)]+(3a-b)/[3(2a+b)]
=(2*3b/4+b)/[2(3*3b/4-b)]+(3*3b/4-b)/[3(2*3b/4+b)]
=(5b/2)/(5b/2)+(5b/4)/(15b/2)
=1+1/6
=7/6
-a^nb^(m+2)与4/5a^5b^(2-3m)是同类项
则a和b的次数对应相等
n=5,m+2=2-3m
n=5,m=0