(a-b/a+b)²×(3a+3b/2a-2b)-(a²-b²/a²)÷(b/a

原式= (a-b)²/(a+b)² × 3(a+b) / [2(a-b)] - (a+b)(a-b) / a² × a/b
= 3(a-b) / [2(a+b)] - (a+b)(a-b) / (ab)
= 3ab(a-b) / [2ab(a+b)] - 2(a+b)²(a-b) / [2ab(a+b)]
= (a-b)[3ab - 2(a+b)²] / [2ab(a+b)]
= (a-b)[3ab - 2a² - 4ab - 2b²] / [2ab(a+b)]
= - (a-b)(2a²-ab-2b²) / [2ab(a+b)]
只能化简到这一步了,你看看是不是题目抄错了