求F(s)=(s-3)/(s^2-7s+6)的laplace逆变换

Factorization
F(s)=(s-3)/(s^2-7s+6)=(2/5)(1/(s-1))+(3/5)(1/(s-6))
Notice that L[e^(at)]=1/(s-a)
we can obtain the inverse Laplace transform of F(s) is 1/5e^t[3e^(5t)+2]