问题描述: y=arccos(1/x)的导数是? 1个回答 分类:数学 2014-12-12 问题解答: 我来补答 cos y = 1/x-siny y' = - 1/x^2y' = 1/(x^2 sin y) sin y = (1 - cos^2 y)^0.5 = (1 - 1/x^2)^0.5y' = 1/[x^2 (1 - 1/x^2)^0.5]= 1 / [x(x^2 - 1 )^0.5] 展开全文阅读