问题描述: 设函数y=y(x)有参数方程{x=1-3t-(t^3) y=1-3t+(t^3)}确定,求该函数的极值 1个回答 分类:数学 2014-09-18 问题解答: 我来补答 dx/dt=-3-3t²dy/dt=-3+3t²y'=(dy/dt)/(dx/dt)=(-3+3t²)/(-3-3t²)=(1-t²)/(1+t²)由y'=0得:t=1,-1dy'/dt=-4t/(1+t²)²y"=-4t/(1+t²)²/(-3-3t²)=(4t/3)/(1+t²)³t=-1时,y" 展开全文阅读