问题描述:
sin(-21π/4) cos(-20π/3) tan(-19π/6)=
sin(-21π/4) cos(-20π/3) tan(-19π/6)
分别=?
要详细过程 解释下~~~~~~~~~~~~~~~~~~~~~~~~
sin(-21π/4) cos(-20π/3) tan(-19π/6)
分别=?
要详细过程 解释下~~~~~~~~~~~~~~~~~~~~~~~~
问题解答:
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