2x^3+3x^2-11x-6=0如何因式分解成(x-α)(ax^2+bx+c)这种形式的啊?

f(x)=2x^3+3x^2-11x-6
f(2)= 16+12-22-6=0
x-2 is a factor
let
f(x) = (x-2)(2x^2+ax+b)=2x^3+3x^2-11x-6
coef.of constant => b=3
coef.of x
b-2a=-11
a=7
f(x) = (x-2)(2x^2+7x+3)
再问： f(2)中的2是怎么回事情？是不是2X^3的系数的相反数啊？
再答： f(x) =2x^3+3x^2-11x-6 f(2)= 2(2)^3+3(2)^2-11(2)-6 = 16+12-22-6=0