问题描述: cos(x-pai/4)=根号2/10,x属于(pai/2,3pai/4)求sinx和sin(2x+pai/3) 1个回答 分类:数学 2014-12-14 问题解答: 我来补答 cos(x-π/4)=cosxcosπ/4+sinxsinπ/4=√2/2*(cosx+sinx)=√2/10sinx+cosx=1/5cosx=1/5-sinx平方cos²x=1-sin²x=1/25-2/5*sinx+sin²xsin²x-1/5*sinx-12/25=0(sinx-4/5)(sinx+3/5)=0由x范围sinx>0sinx=4/5cosx=1/5-sinx=-3/5sin2x=2sinxcosx=-24/25cos2x=cos²x-sin²x=-7/25sin(2x+π/3)=sin2xcosπ/3+cos2xsinπ/3=-(24+7√3)/50 展开全文阅读