计算(27+18/19)/9 (51/10+17/38)*51分之19 (2又5分之4+1又7分之4)-(2又5分之4-

问题描述:

计算(27+18/19)/9 (51/10+17/38)*51分之19 (2又5分之4+1又7分之4)-(2又5分之4-1又7分之4)
17/(17+17/20) 108*(1/3+1/6+1/9)
1个回答 分类:数学 2014-11-25

问题解答:

我来补答
(27+18/19)/9
=27÷9+18/19÷9
=3+2/19
=3又2/19

(51/10+17/38)*51分之19
=51/10x19/51+17/38x19/51
=19/10+1/6
=57/30+5/30
=62/30
=31/15

(2又5分之4+1又7分之4)-(2又5分之4-1又7分之4)
=(2又4/5-2又4/5)+(1又4/7-1又4/7)
=0+0
=0

17/(17+17/20)
=17÷[17x(1+1/20)]
=17÷17÷21/20
=20/21

108*(1/3+1/6+1/9)
=108x1/3+108x1/6+108x1/9
=36+18+12
=66
 
 
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