问题描述: π/2≤x≤π/2时,函数y=sinx+根号3cosx的最大值,最小值, 1个回答 分类:数学 2014-10-24 问题解答: 我来补答 y=2(sinxcosπ/3+cosxsinπ/3)=2sin(x+π/3)x=π/6属于[-π/2,π/2],ymax=2x=-π/2属于[-π/2,π/2],ymin=sin(-π/6)=-1/2 展开全文阅读