问题描述: 如图,BP,CP分别平分∠ABC和∠ACB,求证:∠BPC=90°+1/2∠A 1个回答 分类:数学 2014-11-13 问题解答: 我来补答 ∠BPC + ∠PBC +∠PCB = 180∠BPC+1/2∠ABC+1/2∠ACB=180 (1)∠A +∠ABC+∠ACB=1801/2∠A+1/2∠ABC+1/2∠ACB=90 (2)(1) — (2) 得:∠BPC=90°+1/2∠A 展开全文阅读