已知等差数列{An}的前n项和为Sn,且A3=5,S6=36.

1）.S6=6*A3+3*d
=>d=2.=>A1=1
=>An=A1+(n-1)*d=2*n-1
2).Bn=2^An+2*n=2^(2*n-1)+2*n=4^n/2+2*n
Tn=(4^1+4^2+4^3+.+4^n)/2+(2+4+6+.+2*n)
=2*(4^n-1)/3+n*(n+1).