问题描述: lim(x趋向于0)(cosx)^[1/(xsinx)]= 1个回答 分类:数学 2014-11-16 问题解答: 我来补答 lim(x趋向于0)(cosx)^[1/(xsinx)]=lim(x趋向于0)[(1+cosx-1)^(1/(cosx-1))]^[(cosx-1)/(xsinx)]=lim(x趋向于0)e^[(cosx-1)/(xsinx)]=e^lim(x趋向于0)[(cosx-1)/(xsinx)]=e^lim(x趋向于0)[-sinx/(x+xcosx)]=e^(-0.5) 展开全文阅读