已知a分之1减b分之1等于5,那么2a+3ab-2b/a-2ab-b等于多少?1,】

1/a-1/b=5
两边同时乘以ab得
b-a=5ab
则
2a+3ab-2b/a-2ab-b
=(3ab-2(b-a))/(-2ab-(b-a))
=(3ab-10ab)/(-2ab-5ab)
=(-7ab)/(-7ab)
=1