编程实现现输入n为偶数时,调用函数求1/2+1/4+….1/n,当n为奇数时,1/1+1/3+1/5…..1/n,C语言

#include
void main()
{
float sum(int n,int m);
int n;
float s=0;
printf("input the number n:\n");
scanf("%d",&n);
if(n%2==0)
s=sum(n,2);
else
s=sum(n,1);
printf("The sum is %f.\n",s);
}
float sum(int n,int m)
{
int i;
float sum=0;
float k=1;
for(i=m;i