问题描述: log10(e^-xcosπx)求导这道题的正确答案是什么.求大神解答 1个回答 分类:数学 2014-12-11 问题解答: 我来补答 =1/(ln10)[e^(-x)*cos(pi x)]*[e^(-x)cos(pi x)]'=1/(ln10)[e^(-x)*cos(pi x)]*[-e^(-x)cos(pi x)-e^(-x)(-pi sin(pi x))]=[-cos(pi x)+pi sin(pi x)]/[ln(10) cos(pi x)] 展开全文阅读