曲线{x=3t^2/(1+t^2) y=(5-t^2)/(1+t^2) (t为参数)的普通方程是

问题描述:

曲线{x=3t^2/(1+t^2) y=(5-t^2)/(1+t^2) (t为参数)的普通方程是
1个回答 分类:数学 2014-10-22

问题解答:

我来补答
x=3t^2/(1+t^2)
x(1+t^2)=3t^2
x+xt^2-3t^2=0
x+t^2(x-3)=0
t^2(x-3)=-x
t^2=-x/(x-3)
y=(5-t^2)/(1+t^2)
y(1+t^2)=5-t^2
y+yt^2=5-t^2
yt^2+t^2=5-y
t^2(y+1)=5-y
t^2=(5-y)/(y+1)
(5-y)/(y+1)=-x/(x-3)
-xy-x=(5-y)(x-3)
-xy-x=5x-15-xy+3y
-x=5x-15+3y
6x+3y-15=0
2x+y-5=0
 
 
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