问题描述: X+1)除以(x+2)加上(x+6)除以(x+7)等于(x+2)除以(x+3)加上(x+5)除以(x+6)求x 1个回答 分类:数学 2014-12-09 问题解答: 我来补答 (X+1)除以(x+2)加上(x+6)除以(x+7)等于(x+2)除以(x+3)加上(x+5)除以(x+6) [1-1/(x+2)]+[1-1/(x+7)]=[1-1/(x+3)]+[1-1/(x+6)] 1/(x+2)+1/(x+7)=1/(x+3)+1/(x+6) (2x+9)/(x+2)(x+7)-(2x+9)/(x+3)(x+6)=0 (2x+9)(1/(x+2)(x+7)-1/(x+3)(x+6))=0 (2x+9)[(x^2+9x+18)-(x^2+9x+14)]/(x+2)(x+7)(x+3)(x+6)=0 4(2x+9)/(x+2)(x+7)/(x+3)(x+6)=0 2x+9=0 x=-9/2 展开全文阅读