C语言的多项式计算:(2^1)/1!-(2^2)/2!+(2^3)/3!.-(2^100)/100!

#include
#include
main()
{
int i,j,t=1;
double sum=0.0,s=-1.0,k;
for(j=1;j
再问： 如果给你个例子：x/1!-(x^3)/3!+(x^5)/5!.....(-1)^(n-1)*(x^(2n-1))/(2n-1)! #include #include main() { float sum,term,x; int n,k,sign; printf("Input n,x:\n"); scanf("%d%f",&n,&x); sum=x; term=x; sign=1; for(k=2;k