1.若a²+4b²-2a+4b+2=0,求a、b的值 2.已知x、y满足x²+y²

1. a²-2a+1+4b²+4b+1=0
（a-1）²+（2b+1）²=0
a-1=0且2b+1=0
a=1,b=-1/2
2. x²-4x+4+y²-y+1/4=0
（x-2）²+（y-1/2）²=0
x=2,y=1/2