初二因式分解难题

问题描述:

初二因式分解难题
1个回答 分类:数学 2014-10-31

问题解答:

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1/x(x+1) +1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)=5/(x²+11x-708)
1/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)+1/(x+4)-1/(x+5)=5/(x²+11x-708)
1/x-1/(x+5)=5/(x²+11x-708)
(x+5-x)/x(x+5)=5/(x²+11x-708)
x(x+5)=x²+11x-708
-6x=-708
x=118
 
 
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