已知f(x)=sin²x+2sinxcosx+3cos²x,x∈R,求:函数f(x)在区间[0,π/

f(x)=1+sin2x+2cos^2x
=1+sin2x+1+cos2x
=√2sin(2x+π/4)+2
2kπ-π/2≤2x+π/4≤2kπ+π/2
kπ-3π/8≤x≤kπ+π/8
[0,π/8]