求一个表达式的积分?∫1/[x(x+2)]dx也就是 x(x+2) 这个乘积的倒数的积分 ,尽量写上步骤

∫1/[x(x+2)]dx
=0.5∫[2/[x(x+2)]dx
=0.5∫[1/x -1/(x+2)]dx
=0.5∫1/xdx -0.5∫1/(x+2)d(x+2)
=0.5lnx+C1-0.5ln(x+2)+C2
=0.5lnx-0.5ln(x+2) +C