计算下面各题,怎样简便怎样算

问题描述:

计算下面各题,怎样简便怎样算
(2/3)*6/(8/9)=?(3/4)/(6/7)/14=?
(9/10)/(1-(3/8))=?(1/5)+(4/5)*(15/16)=?
(17/2)/15*(5/7)=?(6/5)/4*(2/3)/(1/6)=?
)是一个分数
1个回答 分类:数学 2014-11-29

问题解答:

我来补答
(2/3)*6/(8/9)=?
=6*(2/3)*(9/8)
=6*3/4
=9/2
(3/4)/(6/7)/14
=(3/4)/[(6/7)/14]
=(3/4)/[(6/7)*(1/14)]
=(3/4)/(1/12)
=3/4*12
=9
(9/10)/(1-(3/8))
=(9/10)/1-[(9/10)/(3/8)]
=(9/10)-[(9/10)*(8/3)]
=(9/10)-(12/5)
=(9-24)/10
=-15/10
=-3/2
(1/5)+(4/5)*(15/16)
=(1/5)+3/20
=(4+3)/20
=4/20
=1/5
(17/2)/15*(5/7)
=(17/2)*1/15*5/7
=17/42
(6/5)/4*(2/3)/(1/6)
=(6/5)*1/4*(2/3)*6
=6/5
)是一个分数
 
 
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