如图,AB=CD,AE=DF,CE=BF,求证：AE平行DF

1.CE=BF:CE=CF+EF,BF=BE+EF推出CF=BE,AB=CD,AE=DF,推出三角形ABE全等于三角形CFD,得出角B=角C.
2.已知角B=角C,AB=CD,CE=BF,推出AF=ED.
3.四边形中已知AE=DF,AF=ED,所以：AE平行DF.