解三元一次方程,x+y-z=6,x+3y+2x=1,3x+2y-z=4

x+y-z=6 ①
x+3y+2z=1 ②
3x+2y-z=4 ③
②-①得 2y+3z=-5 ④
3*①-③得 y-2z=14 ⑤
④-2*⑤得 7z=-33 z=-33/7
代入z到④,得y=32/7
代入y和z到①,得x=-23/7
因此 x=-23/7 y=32/7 z=-33/7
o(∩_∩)o