如果方程X²－6X＋M－2=0有实数根,求M的取值范围,并求出方程的实数根

²-4ac≥0
即 (-6)²-4 x 1 x(m-2)≥0
m≤11
x1=[-b+√(b²-4ac)]/(2a)
=[6+√(44-4m)]/2
=3+(√11-m)
x2=[-b-√(b²-4ac)]/(2a)
=[6-√(44-4m)]/2
=3-(√11-m)