急用!解一元二次方程.能用因式分解就用因式分解!

①(6y+5)(6y-5)-24=0
(6y)²-5²-24=0
(6y)²-25-24=0
(6y)²-49=0
(6y+7)(6y-7)=0
y1=-7/6, y2=7/6
②4(x-3)²-x(x-3)=0
4x²-24x+36-x²+3x=0
3x²-21x+36=0
(3x-9)(x-4)=0
x1=3, x2=4
③(x+4)²-(2x-1)=0
(x+4+√(2x-1))(x+4-√(2x-1))=0
④(2t+3)²=3(2t+3)
2t+3=3
t=0
⑤(3-y)²+y²=9
(3-y)²=9-y²=(3-y)(3+y)
(3-y)=(3+y)
y=0
⑥(1+√2)x²-(1-√2)x=0
x((1+√2)x-(1-√2))=0
x1=0
(1+√2)x-(1-√2)=0
(1+√2)x=(1-√2)
x2=(1-√2)/(1+√2)
⑦x²=x+56 必须用因式分解
x²-x-56=0
(x-8)(x+7)=0
x1=8, x2=-7
⑧x-2=x(x-2) 必须用因式分解
x-2=x²-2x
x²-3x+2=0
(x-1)(x-2)=0
x1=1, x2=2
⑨x(5x+4)=5x+4 必须用因式分解
5x²+4x=5x+4
5x²-x-4=0
(5x+4)(x-1)=0
x1=-4/5, x2=1
⑩(x-1)(x+2)=70
x²+x-2=70
x²+x-72=0
(x+9)(x-8)=0
x1=-9, x2=8
⑴(x+1)²+2x(x-1)=0
x²+2x+1+2x²-2x=0
3x²+1=0
x²=-1/3
x1=√(-1/3), x2=-√(-1/3)
⑵(x+1)²-3(x+1)+2=0
x²+2x+1-3x-3+2=0
x²-x=0
x1=0, x2=1
⑶(x-2)²=(2x+3)²
(x-2)²-(2x+3)²=0
((x-2)+(2x+3))((x-2)-(2x+3))=0
(x-2+2x+3)(x-2-2x-3)=0
(3x+1)(-x-5)=0
x1=-1/3, x2=-5
⑷(2x+3)²=4(2x+3)
(2x+3)²-4(2x+3)=0
((2x+3)-4)(2x+3)=0
(2x-1)(2x+3)=0
x1=1/2, x2=-3/2
⑸2(x-3)²=x²-9
2(x-3)²=(x+3)(x-3)
2(x-3)²-(x+3)(x-3)=0
(2(x-3)-(x+3))(x-3)=0
(2x-6-x-3)(x-3)=0
(x-9)(x-3)=0
x1=9, x2=3