设A=2x²-3XY+Y²,B=4X²-6XY-3Y²,且（X-5)和（Y+2)

（X-5)和（Y+2)²是互为相反数
则|x-5|+(Y+2)²0
则x-5=0,Y+2=0
则x=5,Y=-2
3A-2B
=3(2x²-3XY+Y²)-2(4X²-6XY-3Y²)
=6x²-9XY+3Y²-8x²+12XY+6Y²
=-2x²+3XY+9Y³
=-2×25+3×(-10)+9×4
=-50-30+36
=-44