问题描述: 等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn 1个回答 分类:数学 2014-09-17 问题解答: 我来补答 An=[2n/(3n+1)]BnAn-1=[2n/(3n+1)]Bn-1lim(n→∞)an/bn=lim(n→∞)[An-An-1]/[Bn-Bn-1]=lim(n→∞)[2n/(3n+1)][Bn-Bn-1]/[Bn-Bn-1]=lim(n→∞)[2n/(3n+1)]=2/3 展开全文阅读