1+2=(1+2)×2/2=3的规律?

问题描述:

1+2=(1+2)×2/2=3的规律?
1+2= (1+2)×2/2=3
1+2+3=(1+3)×3/2=6
1+2+3+4=(1+4)×4/2=10
1+2+3+4+5=(1+5)×5/2=15
·······································
1+2+3+4+5+················n=(1+n)×n/2
(1)n个连续自然数之和的计算规律用语言叙述是:_________________________.
(2)计算1+2+3+4+··········+99+100
(3)求1+ 1/1+2 + 1/1+2+3 + 1/1+2+3+4 + 1/1+2+3+4+5 +···············+1/1+2+3+4+··········+100的值
1个回答 分类:数学 2014-12-01

问题解答:

我来补答
(1)首项加末项乘以项数除以2
(2)原式=(1+100)*100/2=101*50=5050
(3)设an=1/(1+2+...+n)=2/(n*(n+1))=(1/2)(1/n-1/(n+1))
所以原式=(1/2)(1-1/2+1/2-1/3+...+1/100-1/101)
=1/2*(1-1/101)=50/101
 
 
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