因式分解(x²-2xy)²+2y²(x²-2xy)+y²,

=(x²-2xy)²+2y²(x²-2xy)+y的4次方
=(x²-2xy+y²)²
=(x-y)的4次方
再问： 过程详细一点
再答： =(x²-2xy)²+2y²(x²-2xy)+y的4次方 =(x²-2xy)²+2×(x²-2xy)×y²+(y²)² =(x²-2xy+y²)² =(x-y)的4次方