问题描述: 求由方程cos(xy)=x^2*y^2 所确定的y的微分 1个回答 分类:数学 2014-10-25 问题解答: 我来补答 -sin(xy)[ydx+xdy]=2xy^2*dx+x^2*2ydy-sin(xy)ydx-sin(xy)xdy=2xy^2*dx+2x^2*ydy-2x^2*ydy-sin(xy)xdy=2xy^2*dx+sin(xy)ydx-[2x^2*y+sin(xy)x]dy=[2xy^2+sin(xy)y]dxdy/dx=-[2xy^2+sin(xy)y]/[2x^2*y+sin(xy)x] 展开全文阅读